Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
A manufacturer claims that the mean lifetime, , of its light bulbs is 49 months. The standard deviation of these lifetimes is 9 months. Seventy bulbs are selected at random, and their mean lifetime is found to be 46 months. Can we conclude, at the .01 level of significance, that the mean lifetime of light bulbs made by this manufacturer differs from 49 months?
Perform a two-tailed test. Then fill in the table below
Round to at least three decimal spaces
1. Hypothesis
2. Null Hypothesis
3. Type of Test Statistic; T Z Chi F
4. The two critical values at the .01 level of significance.
5. Can we conclude that the mean lifetime of the light bulbs made by this manufacture differs from 49 months.
A researcher is interested in estimating the noise levels in decibels at area urban hospitals. She wants to be 99% confident that her estimate is correct.
Assume that a decision maker wants to estimate a population proportion with 90% confidence and a margin of error of ±0.03. The decision maker has obtained a pilot sample of 10.
Drawing the standard normal curve and indicating the area representing the probability and
Give a variable that could be used to stratify the population for each of the following studies. List at least four subcategories for each variable.
The average salary for graduates entering the actuarial field is $40,000. If the salaries are normally distributed with a standard deviation of $5,000, find the probability that
a) Explain why it would be hard to take a Simple Random Sample? b) Describe how to take a cluster sample of chocolate chip cookies.
A research study comparing college alcohol use in the United States and Canada reports that more Canadian students drink but American students drink more Is this study an example of an experiment? Explain why or why not.
No, there is not sufficient information to reject the hypothesis that the proportion of cats and the proportion of dogs that sleep more than 10 hours per day are the same because the test value -0.65 is inside the acceptance region (-1.96,1.96).
The normal distribution has several characteristics that make it the underlying foundation of much of inferential statistical tools.
Following a lognormal distribution with a mean of 3000 rpm and std deviation of 0.87, what if the boss want a 5% chance of HW failure before selling, how often would I have to replace this hardware ?
What are the five steps for calculating probabilities of events? Please apply these steps to an example.
Find the critical value for t and determine the null and alternate hypothesis.
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd