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Write the equilibrium law for the reaction calculate the

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A solution containing a mixture of ethanoic acid, ethanol, ethyl ethanoate and water was allowed to come to equilibrium in a stoppered bottle at 373 K, when the amount of each of the four substances was measured. These were found to be as in the table below:

Substance

Amount/mol

Ethanoic acid (CH3COOH)

Ethanol (CH3CH2OH)

Ethyl ethanoate (CH3COOCH2CH3)

Water (H2O)

0.09

0.21

0.18

0.42

The equation for the reaction is:

CH3COOH(aq) + CH3CH2OH(aq) <=> CH3COOCH2CH3(aq) + H2O(l)

a) Write the equilibrium law for the reaction.

b) Calculate the equilibrium constant for the reaction at this temperature.

c) Calculate the equilibrium constant for the reaction:

CH3COOCH2CH3(aq) + H2O(l) <==> CH3COOH(aq) + CH3CH2OH(aq)

d) 0.20 mol of ethyl ethanoate is mixed with 0.60 mol of water in a stoppered bottle. The mixture is kept at 373 Kuntil equilibrium is reached. How many moles of ethanoic acid are present in this mixture?

Reference no: EM13586948

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