Reference no: EM13339015

Write a function named "enough" that takes one integer argument, call it "goal" and returns as its value the smallest positive integer n for which 1+2+3+. . . +n is at least equal to goal . Thus, for example,

cout << enough(9) << endl; // will print 4 because 1+2+3+4 9 but 1+2+3<9
cout << enough(21) << endl;// will print 6 "cause 1+2+ . . .+6 21 but 1+2+ . . . 5<21
cout << enough(-7) << endl;// will print 1 because 1 -7 and 1 is the smallest // positive integer
cout << enough(1) << endl; // will print 1 because 1 1 and 1 is the smallest // positive integer