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Write a routine to list out the nodes of a binary tree in level-order. List the root, then nodes at depth 1, followed by nodes at depth 2, and so on. You must do this in linear time. Prove your time bound.
Assume that what is meant by "list out" is that the method returns a java.util.List<Integer> containing the data from the tree in level order. Add a new method to your BinaryTree class named levelOrder(). You will need to maintain a data structure to help you control the traversal.
You should use something from java.util, but make a good choice that is well-suited to the task at hand. In the comment for levelOrder(), write a brief statement justifying your decision. Test thoroughly.
This is in Java.
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Rewrite the above pseudocode so that it takes into account that T is actually an array.
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questiondescribe what java environment would contain to do if you were trying to pass an arraylist a collection class
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