Reference no: EM132193449

Question: Write a program, using 25 or fewer lines of code, to count each occurrence of each lower-case letter in a string.

Start your program by declaring a character array, msg, with a size of 30 of greater.

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char msg[MAX];

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The user should then type a text string into the array:

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cin.getline(msg, MAX);

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Your program should now report the number of each character (a-z) found in the array:

a face at the beach

a - 4

b - 1

c - 2

d - 0

e - 3

f - 1

g - 0

h - 2

i - 0

j - 0

k - 0

l - 0

m - 0

n - 0

o - 0

p - 0

q - 0

r - 0

s - 0

t - 2

u - 0

v - 0

w - 0

x - 0

y - 0

z - 0

Here is one way of creating that output using characters in a loop:

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for (i=0; i<26; i++)

cout << static_cast<char>(i + 'a') << " - " << etc..

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