Why array names are not assignable variables in c

Assignment Help Computer Engineering

Reference no: EM133444

Question

In programming language C, array names are not assignable variables. Therefore, we can't copy an array directly with an assignment statement. As a contrast, objects of struct types can be copied.

The following code snippet illustrates difference:

struct {int i; float f;} x, y;
int a[10], b[10];
y = x; /* Copy x to y, OK */
b = a; /* Illegal assignment */
Now if we wrap an array inside a struct:
typedef int array[5];
typedef struct {array v;} wrapped;
then we can copy a wrapped array with assignment
wrapped wa, wb;
wb = wa; /* Copy wrapped array a to wrapped array b */
Use this idea to implement an array-copying routine:
/* copy (unwrapped) array a to array b */
void array_copy(array a, array b)
{
}

such that when following driver routine executes,

int main()
{
array a = {1,2,3,4,5}, b = {6,7,8,9,10};
printf("Before: b=[%d,%d,%d,%d,%d]n",
b[0],b[1],b[2],b[3],b[4]);
array_copy(a,b);
printf("After: b=[%d,%d,%d,%d,%d]n",
b[0],b[1],b[2],b[3],b[4]);
}

we get the output:
Before: b=[6,7,8,9,10]
After: b=[1,2,3,4,5]

Reference no: EM133444

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