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Solve the all parts of given problem:
Problem: Two cyclists are 72.9 meters apart. At t = 0, they both start to accelerate toward each other. Both start from rest. Cyclist A has an acceleration of .6 m/s2, and cyclist B has an acceleration of -1.2 m/s2.
Part I: When do the cyclists meet?
Part II: Which cyclist is moving faster when they meet?
Part III: What is the ratio of the distance traveled by the cyclist A to that traveled by cyclist B?
Please explain each step and equations used for above problem.
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