What would its activity be 2 cm from the detector

Reference no: EM13692188

Question- When a sample of phosphorus-32 (a beta-emitter used to treat leukemia and pancreatic cancer) was placed 1 cm from the detector, the intensity of its radiation was measured to be 491 counts per second. What would its activity be 2 cm from the detector? 5 cm?
Can you explain the calculation by using the inverse square law.

Intensity = 1/distance^2

Anyone can tell me how to solve it step by step so that I will be able to understand what is going on?

Reference no: EM13692188

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