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1. Let's assume for this problem that the world is divided into blue-eyed people and brown-eyed people. Let's also assume for the sake of simplicity that there is only one gene responsible for eye color and that the allele for brown eyes (B) is dominant over the allele for blue eyes (b). Let's also assume that blue-eyed people and brown-eyed people randomly intermarry.
a. What would be the ratio of brown-eyed to blue-eyed people in the world?
b. Calculate the probability of two BB people having a blue-eyed child.
c. Calculate the probability of a Bb person and a blue-eyed person having a blue-eyed child. Construct a Punnet square for this.
d. Calculate the probability of two Bb people having a blue-eyed child. Construct a Punnett square for this.
e. Two brown-eyed people have a blue-eyed child. What can we infer about the eye color of the child's grandparents?
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One of these three markers has to have a special property that is not needed in the other two markers. What is this property, which of the three markers possesses it, and why is this important?
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DAALAQTAHRLKGVFAMLN after phosporylation of His through RcsC the following pKas are revelead: N terminus= 9.5 and C-terminus 4.5 Asp side chain: 3.3;
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let A and a represent dominant and recessive alleles whos respective frequencies are p and q in a given interbreeding population at equilibrium (with p+q=1). A) if 16 percent of the individuals in the population have recessive phenotypes.
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A purified, active preparation of carbonic anhydrase was submitted to native polyacrylamide gel electrophoresis at alkaline pH. Three major bands were observed after staining
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What is the probability that their next child will be a taster.
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