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What would be the fraction converted in a half-hour run

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Reference no: EM13857261

Problem 1 (Octave Levenspiel) A 10-minute experimental run shows that 75% of liquid reactant is converted to product by a half-order rate. What would be the fraction converted in a half-hour run?

Problem 2 (Octave Levenspiel) After 8 minutes in a batch reactor reactant (CA0 = 1 mol/L) is 80% converted; after 18 minutes, conversion is 90%. Find a rate equation to represent this reaction.

Problem 3 (Octave Levenspiel) Aqueous A at a concentration of CA0 = 1 mol/L is introduced into a batch reactor where it reacts away to form product R according to stoichiometry

A → R

The concentration of A in the reactor is monitored at various times, as shown below-

Time, min CA, mol/m3

0 1000
100 500
200 333
300 250
400 200

(a) For CA0 = 500 mol/m3 find the conversion of reactant after 5 hours in the batch reactor.

(b) Find the rate expression for the reaction.

Reference no: EM13857261

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