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Question 1:
-2x +1 x < -2
f(x) = x2 + 1 if -2 < x < 1
2x 1 ≤ x ≤ 3
5 x ≥ 3
1.1 Explain with leasons why limx→-2 f(x) exists, but f(x) is not continuos at x = -2. State the type of discontinuity.
1.2 What type of discontinuity exists at x = 3 ?
1.3 Show that f(x) is continuous and diffrent table at x = 1.
1.4 For what value(s) of x is f'(x) = 0
1.5 If g(x) = √2x, determine the value of (gof)(-1)
1.6 If h(x) = 3x2, determine h(g(x)).
Question 2:
2.1 Determine f'(x) from first principles if f(x) = 5/x-2
2.2 differntiate with respect to x:
2.2.1 Dx[√3x5 - 2x4]
2.2.2 f'(x) if f(x) = 5x3(2x + 1)12
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