What is the probability of not a double 6 on a roll

Reference no: EM131939183

The dice game about which Pascal and de Fermat were asked consisted in throwing a pair of dice 24 times. The problem was to decide whether or not to bet even money on the occurrence of at least one "double 6" during the 24 throws of a pair of dice. Because it is easier to solve this problem by finding the complement, take the following steps:

a. What is the probability of not a double 6 on a roll, P(E) = P(y = 12)?

b. What is the probability that y = 12 on all 24 rolls, P(E₁E₂, ... , E₂₄)?

c. What is the probability of at least one double 6?

d. What are the odds of a win in this game?

Reference no: EM131939183

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