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A researcher tested 100 chemical solutions for the presence of a certain element. The sample average was 8.30% with a sample standard deviation of 0.03%. Let μ = the sample average.
For this problem, use the sample standard deviation as an estimate for the population standard deviation and use the standard normal distribution rather than the student-t distribution for the test.
1. Test the null hypothesis μ = 8.35% against the alternate hypothesis μ < 8.35% using a level of significance α = 0.05. Do you reject or not reject the null hypothesis?
2. Repeat the test using a level of significance α = 0.01. Do you reject or not reject the null hypothesis?
3. What is the p-value of the test?
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