What is the new equilibrium extension of the spring

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A block of mass M = 0.8 kg hangs at the end of a massless spring. A smaller block, of mass m = 0.3 kg, is glued to the bottom of M. The spring constant is k = 90 N/m.

(a) In equilibrium, by how much is the spring extended? Now assume that at t = 0, the small block suddenly falls off. As a result, the mass M begins to oscillate up and down.

(b) What is its oscillation frequency now?

(c) What is the new equilibrium extension of the spring?

(d) With what amplitude does the block M oscillate? (e) Write the position of the block M as a function of time.

Reference no: EM13554163

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