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In a sample of 100 female adults, the 95% confidence interval for the number of chin ups completed was 50 ??[95%CI: 40 to 60]. What is the most likely average number of chin ups an females can accomplish at the population level based on this confidence interval.
1.most days you are good. but some days you are bad. each day there is a 99 chance you are good and a 1 chance you are
Which of the following is true about a hypothesis test of the difference in the two proportions?
For a relative risk of 1.53, what is the percent increase in risk?- For a percent increase in risk of 140%, what is the relative risk?
Let x stand for the number of minutes spent at the mall. 100 people are sampled at a time. For the sampling distribution, the mean is 46 minutes and the standar
the regression equation salary 28000 2700 yearsexperience 1900 yearscollege describes employee salaries at ramjac
Find an integer k that the probability is at least .99 that you will find k invoices that overcharge the customer. Use trial and error with the BInomdist function to find k.
probability based on a random experiment.1. the telephone numbers for a region of a state have an area code of 570. the
Given that 30% of US adults are smokers, find the average of the random variable X= # of smokers in a random sample of 50 residents of the USA, also find the variance and standard deviation of X.
The interviewers were told to find a certain number, or quota, of each of several types of people. For example, they might have been told to interview.
Assuming the supplier's claim is true, compute the mean and the standard deviation of the number of defective DVDs in the sample.
1. A city sewer maintenance crew maintained an average of 248 sewer lines per day two years ago. Upon providing more efficient equipment, a sample of 64 sewer-work days shows that a mean of 260 sewer lines were maintained, with a standard dev..
Explain why a linear model is not appropriate.- Re-express the data to straighten the scatterplot.- Create an appropriate model.
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