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Uranium is distributed in a form called yellow cake, which is made from uranium ore. In the second step of the reactions that form yellow cake from uranium ore, uranyl sulfate, UO2SO4, is converted to (NH4)2U2O7. 2UO2SO4 + 6NH3 + 3H2O → (NH4)2U2O7 + 2(NH4)2SO4
a. What is the maximum mass, in kilograms, of (NH4)2U2O7 that can be formed from the reaction of 100 kg of water and 100 kg of ammonia with 481 kg of UO2SO4?
b. Explain why two of these substances are in excess and one is limiting.
If a solution contains 28 g of potassium nitrate per 100 g of water at 25 degrees Celsius, is the solution unsaturated, saturated, or supersaturated
A 2.0 L glass soda bottle filled only with air is tightly capped at 18°C and 686 mmHg. If the bottle is placed in water at 95°C, what is the pressure in the bottle
The oxidation of HSO3(-) by O2 in aqueous solution is a reaction of importance to the processes of acid rain formation and flue gas desulfurization.
A solution containing both Mn2+ and Cd 2+ is saturated with H2S gas, after which the concentration of H is found to be .30 M. will the sulfides of these ions form a precipitate under these conditions
A student wishes to make a soution of lithium hydroxide (LiOH) to a strength of 1.7 mol/L. If he is going to make a total volume of 1.5 L
A sample of silver chromate (Ag2CrO4) has a mass of 24.7 g. (a) How many Ag+ ions are present? ions (b) How many CrO42- ions are present? ions (c) What is the mass in grams of one formula unit of silver chromate? g/formula unit
use the radius of a sodium atom from the elements handbook to calculate the number of sodium atoms in a row 5.00 cm
Consider the reaction, 2 Al(s) + 3 Cl2(g) => 2 AlCl3(g). How many grams of AlCl3 will be made by the reaction of 7 moles of Al(s) with 27 moles of Cl2(g)
The reaction of methane and water is a way to prepare hydrogen according to CH4(g)+H2O=CO2(g)+H2(g) a) If 995 g of CH4 reacts with 2510 g of water, how many moles of reactants and products are there when the reaction is finished
Problem- you need to prepare 100 mL of a pH=4.00 buffer solution using .100 M benzoic acid (pKa = 4.20) and .160 M sodium benzoate, mL Benzoic acid =
Problem- The endpoint of your titration occurs after you add 13.26mL of 0.5643 M NaOH. The linear regression line for your pH vs. NaOH graph is Y=0.13x+4.16. What is the pKa of your acid
72.0 mL of a 1.40 M solution is diluted to a volume of 278 mL. A 139-mL portion of that solution is diluted using 161 mL of water. What is the final concentration.
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