Reference no: EM132351263
A random sample of 338 medical doctors showed that 180 had a solo practice.
(a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.)
(b) Find a 99% confidence interval for p. (Use 3 decimal places.)
lower limit
upper limit
Give a brief explanation of the meaning of the interval.
A) 99% of the all confidence intervals would include the true proportion of physicians with solo practices.
B) 1% of the confidence intervals created using this method would include the true proportion of physicians with solo practices.
C) 1% of the all confidence intervals would include the true proportion of physicians with solo practices.
D) 99% of the confidence intervals created using this method would include the true proportion of physicians with solo practices.
(c) As a news writer, how would you report the survey results regarding the percentage of medical doctors in solo practice?
A) Report p^ along with the margin of error.
B) Report the margin of error.
C) Report the confidence interval.
D) Report p^.
What is the margin of error based on a 99% confidence interval? (Use 3 decimal places.)