Reference no: EM132854292

For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.

In a marketing survey, a random sample of 1010 supermarket shoppers revealed that 262 always stock up on an item when they find that item at a real bargain price.

(a) Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.)=

(b) Find a 95% confidence interval for p. (For each answer, enter a number. Round your answers to three decimal places.)

lower limit=

upper limit=

Give a brief explanation of the meaning of the interval. which one?

We are 5% confident that the true proportion of shoppers who stock up on bargains falls above this interval.
We are 95% confident that the true proportion of shoppers who stock up on bargains falls outside this interval.
We are 95% confident that the true proportion of shoppers who stock up on bargains falls within this interval.
We are 5% confident that the true proportion of shoppers who stock up on bargains falls within this interval.

(c) As a news writer, how would you report the survey results on the percentage of supermarket shoppers who stock up on items when they find the item is a real bargain? which one?

Report the confidence interval.
Report p^.
Report p^ along with the margin of error.
Report the margin of error.

What is the margin of error based on a 95% confidence interval? (Enter a number. Round your answer to three decimal places.)=