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Solve the all parts of given question:
Question: Incident photons of energy 10.90 keV are Compton scattered, and the scattered beam is observed at 44.95° relative to the incident beam.
Part A: What is the energy of the scattered photons at that angle?
keV
Part B: What is the kinetic energy of the scattered electrons?
Having trouble with this physics question, can you please explain with the answer.
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