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50.0 ml of 0.987 M HCl was mixed with 50.0 ml of 1.02 M NaOH, the heat of neutralization was calculated to be -2.7 kJ. What is the enthalpy (molar heat) of neutralization?
If each mole of gas occupies 55 L under the conditions of the explosion, how many liters of gas are produced? c) how many grams of N2 is produced in the detonation?
200 drops of 0.025 M NaF solution and 100 drops of 0.025 M Ba(NO3)2 solution are mixed. a.) write the equation for the formation of solid BaF2.
copper-64 is used to study brain tumors. assume that the original mass of a sample of copper-64 is 26.00g. After 64 hours, all that remains is 0.8125g of copper-64. What is the half-life of this radioactive isotope?
How many grams of water should be produced and What is the theoretical yield of nitrogen?
The molar heat of neutralization from hydrochloric acid and sodium hydroxide is -57.3 kj/mol. What is the heat evolved during the neutralization of 655ml of 1.00M hydrochloric acid by 1.00M sodium hydroxide?
The introduction state that often the rate doubles for each temperature increase of 10degree celcius. What value of the activation energy would cause the rate to double between 25~35degree celcius? ((k value)
By Solving this problem student understand about isotopic abundance and how to calculate atomic weight (average atomic mass) of an element -
At 0.0 degrees C, if the volume of air is 2.5 mL and the pressure of the atmosphere that day is 805 mmHg, what is the number of moles of air.
This strontium isoptope is radioactive, with a half-life of 28.1 years. Calculate how long (in years) it will take for 5.63g of the isotope to be reduced to .354g by decay
Use MO theory to predict the net bond order after N2 interacts with a photon that results in the promotion of an electron from bonding to an antibonding orbital.
The minerals chalcocite (Cu2S) and malachite (Cu2CO3(OH)2) are two primary sources of copper. What is the oxidation state of copper in each of these minerals?
A synthetic organic chemist wants to make 100.0 grams of benzoyl chloride C7H5OCl from benzoic acid C7H6O2 in the following reaction.
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