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Solve all parts of following question given below:
Question: A 4.80-A current runs through a copper wire of DIAMETER 2.050 mm and through the filament of a light bulb to which the wire is attached. Copper has 8.50 multiply.gif 1028 free electrons per cubic meter.
Part I: How many electrons pass any cross-section of the wire, or any cross-section of the filament, each second?
N = electrons per second
Part II: What is the current density in the copper wire?
J = A/m2
Part III: At what speed does a typical electron pass by any given point in the copper wire?
vd = m/s
Please write the step and answer. How do you work this question? Thanks!
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