Solution-What is the copr of cycle

What is the copr of cycle

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Reference no: EM132058590

An ideal vapor compression refrigeration cycle using r134a as the refrigerant is being used to cool a house. It provides 3 refrigeration tons (= 10.5kW) of cooling (heat removal from the house air). The refrigerant in the evaporator operates at 400kPa while in the condenser it is at 1000kPa. Treat the surroundings as a thermal reservoir at 33C and the air in the house as a thermal reservoir at 19C. All reservoirs are at 100kPa.

What is the COPr of this cycle?
How fast is exergy destroyed (kJ/s) in each process (evaporator, condenser, throttle, compressor)?
Which process has the lowest second law eciency?
What is the rate of exergy destruction (kJ/s) for the cycle?

Please provide detailed answer with all calculations

Reference no: EM132058590

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What is the copr of cycle

Reference no: EM132058590

Reference no: EM132058590

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