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The following heats of formation are used to find the change in enthalpy for the formation of tin chloride in the following reaction Sn (s) + 2Cl2(g) --> SnCl4(l).
Sn(s) + Cl2(g) --> Sn Cl2(l)DH = -186.2 kJSnCl2(s) + Cl2(g) --> SnCl4(l)DH = -325.1 kJ
What is the change in enthalpy?
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