What is the amount of power dissipated by the resistor

Assignment Help Electrical Engineering
Reference no: EM131135606

1. The engineering prefix symbol for 1 x 10+6 is

k.
M.
m.
ì.

2. A series circuit consists of a 100 , a 1 k and a 1 M resistor. What is the total resistance?

< 100
313.3
510
> 1 M

3. A 100 resistor is in parallel with a 220 resistor. The total resistance of the circuit is

<100 .
>100 and <220 .
>220 .
>320 .

4. Express 5000 kV as MV.

0.005 MV
5.0 MV
50 MV
50,000 MV

5. What is the result of 250 mV/50 µ V?

5
50
500
5,000

6. A series circuit has a voltage supply of 6 V and a resistor of 2.0 kΩ. What is the amount of power dissipated by the resistor?

0.003 W
0.018 W
12 kW
72 kW

7. A two resistor voltage divider consists of a 10 k and a 15 k ohm resistor, with the 10 k resistor connected to the voltage source and the 15 k resistor connected to ground. If the output voltage is 2.5 V, what is the value of the voltage source?

2.500 V
4.167 V
6.25 V
7.125 V

8. Express 50 milliamp in engineering notation.

50 x 10-3 A
5.0 x 10-2 A
5.0 A
50 x 10+3 A

9. An uncharged capacitor and resistor are connected in series with a 12 V source and a switch. What is the voltage across the capacitor after the switch is closed and the capacitor is fully charged?

0 V
6.0 V
12 V
24 V

10. A perfect capacitor with C = 0.3 µF is connected in series to a current source with and peak value of 10 V. What is the reactance of the capacitor?

132.6
25.13 m
-25.13
-132.6 m

11. What is the relationship between current (I) and voltage (V) in a circuit consisting of a capacitor in series with a resistor?

I and V are in phase across the capacitor.
I leads V across the resistor.
V leads I across the capacitor.
I and V are in phase across the resistor.

12. If the output impedance of a certain driving circuit is 50 - j10 , what value of load impedance will result in the maximum power to the load?

50 + j10
50 - j100
10 + j50
10 - j50

13. Find the complex conjugate of 250 + j433 in polar form.

250 60
250 -60
500 60
500 -60

14. A voltage source has the values VS = 25 V and RS = 5 . What are the values for the equivalent current source?

5 A, 5
25 A, 5
5 A, 125
5 A, 25

15. In a high-pass filter, XC = 500 and R = 2.2 k . What is the output voltage (Vout) when Vin = 10 V rms?

8.25 12.8º
9.75 12.8°
8.25 36.2º
11.22 28.5º

16. What is The equation to calculate the cutoff frequency in an R-C filter?

17. A sinusoidal voltage with a peak-to-peak value of 15 V is applied to an RC low-pass filter. If the capacitive reactance at the input frequency is zero, the output voltage is

0 V.
7.5 V peak-to-peak.
10.6 peak-to-peak.
15 V peak-to-peak.

18. The output signal of a common-emitter amplifier is always

in phase with the input signal.
out of phase with the input signal.
larger than the input signal.
equal to the input signal.

19. A common-source FET amplifier has an RD = 1.0 k . How much does the gain change when a load resistance of 1.0 k is capacitively coupled to the drain?

x ½
x 1
x2
x4

20. In which FET amplifier configuration is the gain less than unity?

common-source
common-gate
common-drain
common-base

21. Determine Vout in the circuit below.

 

2.68 mV
26.8 mV
2.68 V
3.74 V

22. In a 5 V level detector circuit

the noninverting input is connected to +5 V.
the inverting input is connected to +5 V.
the input signal is limited to a 5 V peak value.
the input signal must be riding on a +5 dc level.

23. If the least significant bit of an 8-bit binary-weighted resistor DAC connects to a 150 kΩ resistor, what resistor value is required for the most significant bit?

1637.25Ω
1171.875Ω
18750Ω
1275.25Ω

24. Determine the output voltage for an op-amp comparator circuit with a non-inverting input reference voltage of + 2 VDC and an inverting input signal of - 1 VDC. The op amp reaches output saturation voltages of ±13 V at the limits.

- 13 VDC
- 1 VDC
+ 3 VDC
+ 13 VDC

25. A comparator circuit is an example of an op-amp operating in which type of input mode?

Single-ended
Double-ended
Inverting
Noninverting

Reference no: EM131135606

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