What is ds°' for the reaction at 298 k

Reference no: EM13889523

What is ΔS°′ for the reaction at 298 K if ΔG°′ = -28.3 kJ/mol and ΔH°′ = +3.9kJ/mol?

I'm not sure how to find ΔG°′ without knowing the equilibrium constant (Keq), I think I'm supposed to use this equation: ?G=?H-T?S but I don't know how to get ?G from ΔG°′

Reference no: EM13889523

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