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A new weight-watching company, Weight Reducers International, advertises that those who join will lose, on average, 10 pounds the first two weeks with a standard deviation of 2.8 pounds. A random sample of 50 people who joined the new Weight reduction program revealed the mean loss to be 9 pounds. At the .05 level of significance
A survey of 100 clients of pacific gas and electric resulted in the following frequency distribution of monthly charges.
During the past six months, 73.2% of US households purchased sugar. Assume that these expenditures are approximately normally distributed with a mean of $8.22 and a standard deviation of $1.10. 80% of the households spent more than what amount?
At the .01 significance level, is there a difference in the mean number of times men and Women order take-out dinners in a month? What is the p -value?
Critically discuss understanding the normal distribution and the factors that affect its shape important in solving business and marketing-related questions?
Process data by Excel using its two-way ANOVA without replication program.
Here is a scatterplot of average crawling age versus average outdoor temperature six months after birth followed by a plot of the residuals versus average outdoor temperature six months after birth.
Using random numbers of 0.1562, 0.9821, 0.3409, 0.5594, and 0.7758, compute the time required for each of five simulated maintenance checks of the airplaine's landing gear.
Can the formal hypothesis testing approach be used for non parametric tests? How are parametric and nonparametric statistics different?
A survey conducted by the American Automobile Association of 64 families of size four vacationing in Niagra Falls resulted in an average amount spent per day of $252.45. Assume the population standard deviation of amounts spent per day is estimate..
What is the equation for this regression model?
Calculate table T t . Calculate Computed T c .
The Speedy Oil Change Company advertised a 15-minute wait for an oil change. A sample of 23 oil changes showed a mean time of 16.5 minutes and a standard deviation of 4.3 minutes.
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