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Scores on a test have a mean of 73 and Q3 is 81. The scores have a distribution that is approximately normal. Find P90. (You will need to first find the standard deviation.)
a. 88.8
b. 88.3
c. 87.1
d. 87.6
P(A 1 )= .20, P(A 2 ), and P(A 3 )= .40. P(B 1 I A 1 ) = .25. P(B 1 I A 2 ) = .05. P(B 1 I A 3 )=.10. Use Bayes' theorem to determine P(A 3 I B 1 )
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