Using java write a recursive method static int intsquareroot

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Using java Write a recursive method static int intSquareRoot(int n) {} // return the biggest number whose square is <= n. Assume n >= 0.

Use recursion. No loops allowed. You will need to recurse on n/4 rather than n-1. That's because the method is called with some big values .

If you recurse on n-1 those values will generate a StackOverflowError. Of course Math.sqrt() or other Math class methods are not to be used in your implementation. Y

ou're just coding this using recursion and elementary operations .

Implementation

Hint: intSquareRoot(n) is close to intSquareRoot(n/4) * 2. (Either equal to it or one more than it. You can tell which one, by squaring something.)

Reference no: EM132170654

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