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If I use a pH calculator to find the ph of .035M of citric acid, I get a pH level of 2.32. However, when I try to find the pH by doing -log10(.035*3), then I get a pH of 0.97. Why is this? If it helps, there are .00105 moles of NaOH and by the stoichiometric coefficient, .00035 moles of citric acid.
The equation in question is C6H8O7 + 3(NaOH) -----> C6H8O7Na3 + 3(H2O)
Problem- How many grams of dry NH4Cl need to be added to 1.50L of a .600M solution of ammonia NH3 to prepare a buffer solution that has a pH of 8.51. Kb for ammonia is 1.8 X 10-5, What is the mass of NH4Cl
what is the simplest molecular formula for bupropion which is composed of 65.13% carbon, 7.575% hydrogen, 14.79% chlorine, 5.84% nitrogen and 6.67% oxygen
Which of the following has only a single peak in the proton NMR spectrum
Presume some HO2 with a preliminary concentration of 2.0 × 10-8M could be confirmed at 25 °C. Compute the concentration that would remain after 1.0 s, presuming no other reactions take place.
A voltaic cell consists of an Mn/Mn2+ half-cell and a Pb/Pb2+ half-cell. Calculate Ecell when [Pb2+] = 0.616 M and [Mn2+] = 1.069 M. You should use the reduction potentials for Mn2+ is -1.18 V and for Pb2+ is -0.125 V.
if 32.7 ml of 0.225 m koh is required to completely neutralize 28.0 ml of a ch3cooh solution what is the molarity of
Integrated Rate Law
If 2 volumes of 0.1 M monobasic potassium phosphate, KH2PO4, are mixed with 1 volume of 0.1 M dibasic sodium phosphate, Na2HPO4, what will be the pH of the mixture?
1000g of Na2HPO4 is dissolved in 100mL of water. using mass balance and charge balance deterimne the pH of the resulting.
At a certain temperature, the reaction PCl5(g) PCl3(g) + Cl2(g) has an equilibrium constant Kc=5.8*10^-2. Calculate the equilibrium concentrations if the initial concentrations [PCl5]=2.00M,[PCl3]=.100M, [Cl2]=0.040M
What is the name of the compound (NH4)3PO3? Why is special about this compound? Choose one answer. a. Ammonium phosphate; this covalent compound is made up of two polyatomic ions, ammonium and phosphate.
The solution is filtered and treated with KSCN to precipitate the excess silver as AgSCN. 0.0140 g of AgSCN are recovered. What is the weight percent of KI in the original mixture
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