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Titration of 50 mL sample of acetic acid is performed by dropwise addition of 0.7 M NaOH. A total of 11.9 mL of the base is required to reach the equivalence point. What was the original concentration of acetic acid before the titration began?
From the understanding of colligative properties, how would I design an experiment to measure the freezing point of a material which freezed at -2'c using the same apparatus used in the laboratory and any chemical reagents commonly found in a chem..
one more question KOH(aq) + H3PO4(aq) For the equation given above, enter the total ionic equation and net ionic equation. only get 3 shots and already used two of them. something is missing.
If 0.0050 moles of Hydrogen(g) and Iodine(g) are placed in a 5.00 L flask, the [HI] at equilibrium. Calculate the Kc. Hydrogen(g) + Iodine(g) 2HI(g)
according to the following reaction how many grams of ammonia will be formed upon the complete reaction of 30.1 grams
If density of ethanol is 0.789 g/ml what is the concentration of 5 grams benzene (c6h6) dissolved into 50 grams ethanol (c2h5oh)?
All of the following are strong electrolytes in aqueous solution except _________. a. H2SO4. b. NaCl. c. NH4C2H3O2. d. H2CO3. e. KOH.
The piston is then moved in and the heat rejected by the air reversibly at constant pressure until the volume is= initial volume. compute The net heat flow and the overall change in entropy?
The density of silver is 10.5 g/mL. What is the mass (in grams) of a piece of silver with a volume of 23.6 mL
Lithium iodide has a lattice energy of -7.3 times 10^2kJmol and a heat of hydration of -793kj/mol. Find the heat of solution for lithium iodide.
A mixture of N2, O2, and CO2 has a total pressure of 791. torr. In this mixture the partial pressure of N2 is 115. torr and the partial pressure of O2 is 193. torr.
How many grams of Ag3PO4 can be produced from the reaction of 2.50 L of a 0.200M AgNO3 with an excess of 0.750 K3PO4 solution according to the following equation?
What is the magnitude of the net gravitational force on the mass at the origin due to the other two masses Take the gravitational constant to be = 6.67×10?11 .
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