The zinc content determined by dissolving the ore in hcl

Reference no: EM13162230

The ore was dissolved in 150 mL of 0.600 M HCl, and the resulting solution was diluted to a total volume of 300 mL. A 20.0 mL aliquot of the final solution required 9.61 mL of 0.527 M NaOH for the HCl present to be neutralized. What is the mass percentage (%w/w) of Zn in the ore sample? The zinc content of a 1.23 g ore sample was determined by dissolving the ore in HCl, which reacts with the zinc, and then neutralizing excess HCl with NaOH. Zn+2HCl-->ZnCl2+H2

Reference no: EM13162230

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