The van der waals equation adjusts for properties of gases

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Problem- The van der Waals equation adjusts for properties of real gases with correction factors 'a' and 'b'. Between CO and O2, which would have larger correction factor 'a' and why?

A. CO will have a larger 'a' value because it is larger

B. O2 will have a larger 'a' value because it is larger

C. CO will have a larger 'a' value because it has stronger intermolecular forces

D. O2 will have a larger 'a' value because it has stronger intermolecular forces

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Reference no: EM13687900

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