The reaction of peroxydisulfate ion s2o82- with iodide ion

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The reaction of peroxydisulfate ion (S2O8)2- with iodide ion (I-)is, S2O82-(aq) + 3I-(aq)= 2SO42-(aq) + I3-(aq)

From the following data collected at a certain temperature, determine the rate law and calculate the rate constant.

Experiment (S2O8)2- (M) I-(M) Initial rate (M/s)

1 0.080 0.034 2.2*10^-4

2 0.080 0.017 1.1*10^-4

3 0.16 0.017 2.2*10^-4

Reference no: EM13384894

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