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The mean weight of loads of rock is 51.0 tons with a standard deviation of 6.0 tons. If 16 loads are chosen at random for a weight check, find the probability that the mean weight of those loads is less than 50.6 tons. Assume that the variable is normally distributed.
In a hypothesis test for the population variance, the alternate hypothesis is the population variance doesnot equal 17.0. The significance level to be used is 0.05 and the sample size to be taken is 25. The tablevalue(s) to use from the chi-square di..
For a sample with standard deviation of 10, a score of X = 44 corresponds to z-score of 0.50. Based on this info, determine the sample mean?
question a researcher wants to conduct a beforeafter study on 15 subjects to determine if a treatment results in any
an internet server conducted a survey of 400 of its customers and found that the average amount of time spent online
Solve the equation for x (by taking the logarithms of both sides): All the other exercises have x on the same side (left) so this one has thrown me.
1 the average score for male golfers is 95 and the average score for female golfers is 106 golf digest april 2006.
A random sample of rivets from 2 suppliers were compared to see what the mean diameter was from each and a test to determine whether the population means were the same for the 2 suppliers. Now a comparison of the variation in diameter is needed.
consider the following set of data.19 10 29 52 64 29 85 16 110 59 115 13a calculate the covariance of the set of data.
at one high school the average amount of time tenth-graders spend watching television each week is 21.6 the principal
Suppose that in a hypothesis test with null hypothesis = 13.0 at 0.05, that a value of 11.0 for the sample mean results in the null hypothesis not being rejected.
If member of sales force submits the entertainment expense (dinner cost for four) of $190, must this expense be considered unusually high. Calculate and interpret z- score for each of six entertainment expenses.
The owner of Britten's Egg Farm wants to estimate the mean number of eggs laid per chicken. A sample of 20 chickens shows they laid an average of 20 eggs per month with a standard deviation of 2 eggs per month.
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