The helium has equal the pressure of argon in the container

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Reference no: EM13525367

The time rate of pressure change in a container sue to the effusion of a gas out of a pinhole in the walls of the container is given by
-dp/dt = ubarAp/(4V) ubar= √(8RT/(πM)) where A is the area of the hole, ubar is the average velocity of the gas molecules, and V is the volume of the container. Suppose a one cubic meter container at 300K and one bar pressure containes 80 mol % He and 20 mol % Ar. The container has a pinhole the area of which is one square millimeter. How long will it take for the pressure of the helium to equal the pressure of the argon in the container? When the pressure are equal what will the total pressure in the container be?

Reference no: EM13525367

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