The formation of the complex ion affect the solubility

Reference no: EM13713651

Question- Copper(I) chloride is relatively insoluble in water with a Ksp of 1.7*10^*-7. However, in the presence of excess chloride ion, the complex ion CuCl2(Kf = 3.0*10^5) forms.

a. How does the formation of the complex ion affect the solubility of copper(I) chloride? Why?

b. How many grams of copper(I) chloride will dissolve in 2.00 L of 5.00 M NaCl?

I want you to elucidate the chemistry in this above problem.

Reference no: EM13713651

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