The equivalence point naoh to the hcl

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Reference no: EM13159408

Assume that the initial volume of the HA solution equals the volume of water used to dissolve you solid acid HA a) using the value of ka from your titration curve, calculate the pH at the equivalence point i got a ka=1.6x10^-4 mol/L, added 100mL of water to my solid acid of 1.212g, and added 10.7mL of NaOH to the HCl to reach the equivalence point i know you need to use [A-]= moles of HA/(vol water added+vol NaOH added) and believe moles of HA=5.39x10^-3

Reference no: EM13159408

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