The equivalence point and 5 ml past the equivalence point.

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A solution containing 100.0 mL of 0.135 M CH3COOH (ka=1.8E-5) is being titrated with 0.54 M NaOH. calculate the ph: at the equivalence point and 5 mL past the equivalence point.

how much is 5 mL past? i do not know how to do it?

Reference no: EM13697479

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The equivalence point and 5 ml past the equivalence point. : A solution containing 100.0 mL of 0.135 M CH3COOH (ka=1.8E-5) is being titrated with 0.54 M NaOH. calculate the ph: at the equivalence point and 5 mL past the equivalence point.

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