The distance light moves in one secondta xayaza 45 s13 ls 3

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Reference no: EM13580384

Event A happeneds at the space time coordinate (1 lightsecond (ls) is the distance light moves in one second),(Ta, Xa,Ya,Za)= (4.5 s,1.3 ls, .3 ls, 5.6 ls) in a frame S, and event B happeneds at the coordinates (t'b,x'b,y'b,Z'b)= (-1.4 s, 29.1 ls, .3 ls, 5.6 ls) in another frame S' which is moving along in the +x-axis at a speed u=.550c relative to the frame S.

Calculate the time interval between events A and B in the frame S, and in the frame S'.

Number:

tb-ta=?

t'b-t'a=?

Choose One:

A. In both frames S and S', and event B happeneds first then A.

B, In frame S, event A happens first then B, while in frame S' it is the opposite.

C. In frame S, event B happens first then A, while in frame S', it is the opposite.

D. In both frames S and S', event A happens then event B.

Reference no: EM13580384

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