Reference no: EM13943662
Combustion problem NO - 14
A boiler is fired using 200 kg /hr of pure saturated hydrocarbon gas ( Cn Hm ) at atmospheric pressure and 20 oc. The dry analysis of the flue gas which leaves the boiler at atmospheric pressure and 300 oc is CO2 = 12%
CO2 =12% , O2 = 3% , N2 =80 % ,
Estimate the formula of the fuel and total volumetric rate of the gas .
SOLUTION -
Basis - 100 kg mole of dry flue gas-
O2 in flue gas = 85 kg mole
O2 supplied by air = 85 *21/79 = 22.59 kg mole
O2 reported in flue gas = O2 as CO2 + O2 as O2 = 12+3.0 =15 .0 kg mole
O2 unaccounted = O2 reacted with H2 = 22.59 -15.0 =7.59 kg mole
H2 REACTED =7.59*2 = 15.18 kg mole = 15.18 *2 =30.36 kg mole
Formula of the fuel ( hydrocarbon ) gas -
Atom of carbon = 12 kg atom
Amount of hydrogen = 30.36 atom
Atom of H /Atom of C = 30.36/12 = 2.53
As the ratio is more than 2.0 , hence it is paraffin of formula , CnH2n +2
Hence , n /2n+2 = ½.53
N = n =3.77 = 4.0
Hence the fuel is n- butane = C4H10
Volumetric flow rate --
Amount of fuel = 200/58 = 3.45 kg mole/hr
Assuming ideal gas , volume at 20oc and 1 atomsphere . is-
V= n.R.T/P = 3.45 *0.082 *(273+20) /1.0 = 82.95 m3 /hr
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