Surface obtained by revolving the curve

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Find the area of the surface obtained by revolving the curve: y=√(2 + 3x), 0≤x≤2 about the x-axis.

The answer is (pi/18)((41)3/2 - (17)3/2)...... but I got (pi/6)((25)3/2 - (9)3/2). Where did I go wrong? My professor seems to have a (1/3) outside of the radical and I am not sure where it came from. Your helpful explanation is much appreciated!

Reference no: EM132059900

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