Suppose a stone is thrown upward with an initial velocity

Reference no: EM13583328

Suppose a stone is thrown upward with an initial velocity of 44 ft per second and is released 4 ft above the ground. Its height "h" in feet after "t" seconds is given by h(t)= -16t^2 + 44t + 4. a) When does the stome reach a height of 32 ft?

After how many seconds does the stome reach it maximum height and what is the height?

Reference no: EM13583328

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