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If 3.00 g of PbO2 was allowed to react with 2.00 g of Pb and 2.00 g of sulfuric acid, then 0.0116 mol of PbSO4 was obtained. What was the percent yield of PbSO4 (by weight) for this reaction?
PbO2+Pb+2H2SO4--> 2PbSO4+2H2O
PbO2 molecular weight= 239.2
Pb molecular weight= 207.2
H2SO4 molecular weight=98.1
PbSO4 molecular weight=303.3
H2O molecular weight=18.01
percent yield of PbSO4 (by weight) for this reaction?
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