State what is the maximal amount of lead iodide

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What is the maximal amount of lead (II) iodide (the theretical yield) that can be obtained when 0.75 moles of lead (II) nitrate and 83 g potassium iodide are mixed together and let to react according to the following unbalanced chemical equation:

KI(aq) + Pb(NO3)2 (aq) = PbI2(s) + KNO3 (aq)

Calculate percent yield if 76g PbI2 is actually obtained in this experiment

Reference no: EM13187632

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State what is the maximal amount of lead iodide : What is the maximal amount of lead (II) iodide (the theretical yield) that can be obtained when 0.75 moles of lead (II) nitrate and 83 g potassium iodide are mixed together

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