State the percent yield when 28.16 g of co2

Reference no: EM13535203

Give the percent yield when 28.16 g of CO2 are formed from the reaction of 4.000 moles of C8H18 with 4.000 moles of O2. 2 C8H18 + 25 O2 ? 16 CO2 + 18 H2O

Reference no: EM13535203

Questions Cloud

Compute how far has the spring been compressed : A block of mass 12.0 kg slides from rest down a frictionless 35.0° incline and is stopped by a strong spring with k = 2.80 104 N/m. how far has the spring been compressed

What is the increase in internal energy in the sledge : A sledge loaded with bricks has a total mass of 17.0 kg and is pulled at constant speed by a rope. What is the increase in internal energy in the sledge and the surface due to friction

Explain the empirical formula for the compound c 5h2o : Combustion analysis of 63.8 mg of a C, H and O containing compound produced 145.0 mg of CO2 and 59.38 mg of H2O. What is the empirical formula for the compound? A) C 5H2O B) C 3H6O C) C HO D) C 6HO3 E) C 3H7O

Evaluate the final velocity of the composite object : An object of mass 2.93 kg, moving with an initial velocity of (4.90i) m/s, Find the final velocity of the composite object

State the percent yield when 28.16 g of co2 : Give the percent yield when 28.16 g of CO2 are formed from the reaction of 4.000 moles of C8H18 with 4.000 moles of O2. 2 C8H18 + 25 O2 ? 16 CO2 + 18 H2O

Prepare an income statement for april : Prepare an income statement for April, a statement of owner's equity for April, and a balance sheet as of April 30 - effect of each transaction and the balances

Calculate how much work is required to pull him : How much work is required to pull him a distance of 58.0 m up a 27.0° slope (assumed frictionless) at a constant speed of 1.80 m/s

Determine the proper amounts - analyzing interrelationships : Analyzing the interrelationships among the four financial statements, determine the proper amounts for (a) through (q).

Evaluate the delta h for the reaction ch4(g) + 4cl2(g) : calculate the delta H for the reaction:CH4(g) + 4Cl2(g) --> CCl4(g) + 4HCl(g). Use the following data: C(s) + 2H2(g) --> CH4(g) delta H = - 74.6 kJ; C(s) + 2Cl2(g) --> CCl4(g) delta H = - 95.7 kJ; H2(g) + Cl2(g) --> 2HCl (g) delta H = - 92.3 kJ

User Account

All Pages