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State the null and alternative hypotheses

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The average price of homes sold in the U.S. in 2012 was $240,000. A sample of 144 homes sold in Chattanooga in 2012 showed an average price of $246,000. It is known that the standard deviation of the sample is $36,000. We are interested in determining whether or not the average price of homes sold in Chattanooga is significantly more than the national average.

-----------------------Look, I already understand how to find the test statistic. I know it is 2. I just do not get how to find the critical Value WITHOUT a TI 93 calculator just the z and t charts. Really the only thing I need explained is how on earth to find the critical value.

a. State the null and alternative hypotheses to be tested.

b. Compute the test statistic.

c. The null hypothesis is to be tested at 95% confidence. Determine the critical value(s) for this test.

d. What do you conclude?

Reference no: EM131050640

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