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How many milliliters of 1.00 M KOH should be added to 100 mL of solution containing 10.0 g of histidine hydrochloride (His HCl,FM 191.62) to get a pH of 9.30?
First, divide 10.0g by 191.62g/mol to get 0.052187 mols of histidine HCl, pKa of 6.5.
Then, using pH = pKa + logx/.052187-x, the x is found to be 0.0521 mols of OH-.
From this point, should I multiply 0.0521 by 1.0M or by the molecular weight of KOH? I think I should multiply by 1.0M which would yield 52.1mL of KOH. If anyone can verify the accuracy of this answer, please respond.
Show all the steps in the mechanism for the following reaction, When benzene is mixed with deuterated sulfuric acid, deuterium is slowly incorporated onto the ring. Show the mechanism for this reaction and explain how this relates the sulfonation of ..
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