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During a titration, the following data were collected. A 25 mL portion of a solution of an unknown monoprotic acid was titrated with 1.0 M NaOH(aq). It required 65 mL of the base to neutralize the sample. How many moles of acid are present in 3.0 liters of this unknown solution?
A solution has a volume of 2.0 L and contains 36.0 g of glucose. If the molar mass of glucose is 180g/mol, what is the molarity of the solution? Answer must be expressed in dimension analysis.
Even with a drying tube, leaving phenylmagnesium bromide exposed to air will eventually lead to its decomposition. Why? What is the product of this decomposition pathway?
must be dissolved in 15.0g of camphor to lower its freezing point by 2 degrees celsius? constant k of camphor = 37.7 (*C x kg)/mol
What are the RATE LAW and k VALUE (with units) for the reaction? Assume conc. in moles per liter T or F. Feezer burn involves solid water conversion to vapor then back again.
Given the reaction PCl5 goes to PCl3 and Cl2. Starting with PCl5, calculate the equilibrium mole fractions of all species at 500 kelvin and 1.00 bar
"Based upon what you know about the accepted mechanism for hydration, can you see any reason why this hydration should be 100% stereoselective?"
what is the solubilty of O2 at an elevation of 12, 000 ft where the atmospheric pressure is 0.657 atm? Assume the temperature is 25 degrees celsius, and that the mole fraction of O2 in air is 0.209 at both 12, 000 ft and at sea level.
Considering the mixture of the two compounds and range of the melting points, the reason recrystallization was difficult was due to a broad melting point range.
it is found that 1.431g of element x ciontains 7.509 *10^21 atoms. calculate the atomic mass of x
Determine the ΔH solution for this compound If the heat of solvation for this compound = -30.8 kJ/mol , crystal lattice energy = -62.2 kJ/mol.
a container holds 2,0 of gas. the total average change in KE of gas molecules in the container is equal to the the sum of KE of an 8,0x10^-3 -Kg bullet with speed
calculate the final molarity of the solution that results when 125 ml of .200 M HCL is diluted to 1.00L
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