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1. Use stereoformulas to show that (S)-benzoin reduces to meso-hydrobenzoin.
2. Using stereoformulas, show that reduction of (R)-benzoin from the more hindered face would give give (R,R)-hydrobenzoin.
Using a solution containing 0.302 grams of an antibiotic has an osmotic pressure of 8.34 mmHg At 23.6°C, 0.500 L. calculate its molecular mass.
volumetric flask and this solution becomes quite warm, but after it is permitted to return to room temperature, H 2 O is combined to total 500 mili litres of solution. Compute the pH of the final solution. ?
Magnesium is used in lightweight alloys for airplane bodies and other structures. The metal is obtained from seawater in a process that includes precipitation, neutralization, evaporation
What mass of this substance must evaporate in order to freeze 160 g of water initially at 19 C? (The heat of fusion of water is 334 {J/g}; the specific heat of water is 4.18 {J/g c. K}.)
When a container is filled with 3.00 mol of H2 , 2.00 mol of O2 , and 1.00 mol of N2 , the pressure in the container is 465 kPa. determine the partial pressure of O2?
A test solution contained 2 mL of 0.10 M Ag+. A silver strip was dipped into the test solution, and a cell potential of 0.0592 V was measured against an Ag/Ag+(1.0M) reference half-cell.
Calculate the value of the rate constant for this reaction at 375 degrees celsius. I already calculated the activation energy which is 140.3 kj.
If it takes 526 J of energy to warm 7.40 g of water by 17 °C, how much energy would be needed to warm 7.40 g of water by 55 °C?
Consider the following qualitative analysis scenario and then classify what type(s) of qualitative analysis principle is/are being used. More than one choice may be correct.
How many grams of formic acid, HCOOH, must be added to 0.100 L of 0.130 M sodium formate, HCOONa, to yield a buffer solution with a pH of 4.40? Assume no volume change. Ka of HCOOH = 5.0 10-4.
4HCl + MnO2 = MnCl2 + 2H2O + Cl2 When 1.22 mol of HCl reacts with excess MnO2, how many moles of Cl2 form?
When 2.00 mol of NOCl(g) was heated to 225 degrees celcius in a 400L steel reaction vessel, the NOCl partially decomposed according to the equation 2 NOCl(g) -->2 NO(g) + Cl2(g)
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