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An Associated Press story (March 8, 2006) about a survey commissioned by the American Medical Association of a nationwide random sample of 644 college women or graduates ages 17 to 35 estimated that a proportion of 0.74 of women on Spring Break use drinking as an excuse for outrageous behavior. including public nudity and dancing on tables. Find the standard error of this estimate. and interpret.
The hypothesis is to be tested at the 5% level of significance. The critical value from the table equals:
Find out the expected winnings for a person who buys one ticket.
Using symbols state hypotheses (H 0 and H 1 ) for two-tailed test. Sketch suitable distribution and locate critical region for a = 0.05.
Calculate probability that the sample would have a mean:
An advantage of the permutation test over the t test for a difference in means is that - distribution interval or a bootstrap percentile interval
A sample of 81 business managers on the West Coast had an average breakfast cost of $7.65. 13. At a = 0.05, what is the test value?
Findout the margin of error for this survey if we want a 99 percent confidence in our estimate of the percent of adults over 50 who take vitamin supplements.
Consider the following stemplot. The mean of the data represented in this stemplot ?
The mean amount of time a (unnamed) computer server is down is 18.3 minutes with a standard deviation of 5.7 minutes.
I have fit a line to data representing cholesterol readings for 28 individuals starting a cholesterol reducing drug. The computer provides the following output, The degrees of freedom for the t test for the slope are
The best estimator or appreciative for the population proportion is 0.45. How large must the sample be?
Find the probability and mean and standard deviation for given data under Binomial distribution.
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